EPISODE · Feb 28, 2022 · 11 MIN
2⁰=1を群論で証明
from すうがくのおやつ🍰 · host タイキ
#すうがくのおやつ #数学 #レター募集中 #0乗 #群論 f:R+→R× x →2ˣ f(x+y)=2ˣ⁺ʸ =2ˣ×2ʸ =f(x)×f(y) fは準同型 よってR+の単位元（0）はfによってR×の単位元（1）になる つまり2⁰=1 --- stand.fmでは、この放送にいいね・コメント・レター送信ができます。 https://stand.fm/channels/5f56277b6a9e5b17f7f4ee68
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2⁰=1を群論で証明
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