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FQII - TCG - 1.16 episode artwork

EPISODE · Sep 28, 2020 · 4 MIN

FQII - TCG - 1.16

from MMM · host Márcio

Obtenção da velocidade mais provável por meio da derivada de Gv(dv) em relação a v. G'(v) dv = 0 (condição de máximo) vmp = sqrt(2kBt/m) ou sqrt (2RT/M)

Episode metadata supplied by the publisher feed · Published Sep 28, 2020

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FQII - TCG - 1.16

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