EPISODE · Oct 16, 2020 · 2 MIN
Q1. Two right triangles ABC and DBC are drawn ion the same hypotenuse BC and on the same side of BC. If AC and BD intersect at P, prove that AP x PC = BP x PD.
from Similar to triangle (Part 5) | Some Applications of Trigonometry | CBSE | Class 10 | Math
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Q1. Two right triangles ABC and DBC are drawn ion the same hypotenuse BC and on the same side of BC. If AC and BD intersect at P, prove that AP x PC = BP x PD.
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